Online solutios

head

DESIGN OF SOLAR BASED PHOTOVOLTAIC WATER PUMPING FOR IRRIGATION USING SUN TRACKING SYSTEM

 Determine motor pump power

 Motor pump power is 2HP which is the same as 1492W, I want to design the system to be able to run for 8 hours during from morning the rising of the sun till evening when the sun is down

Determine servo motor power needed
>Mass of a single panel is 22kgs, the length of the panel is 1.5m and the width of the panel is 1m
>Power of the motor. 
From the equation (newton 2nd law of motion) 
>F=ma
>m = 22kgs and a = 9.81m/s2
>F=22kg x 9.81m/s2
>F = 215.82N




The average insolation over a year’s average, which is obtained from table above as 5.1 KW/m2/day.
>panel generation factor is 0.61
>Energy lost in the system is 1.3
Amount of Solar power needed = total watt-hour×1.3(energy lost in system) ÷ (0.62 ×5.1) 
Solar power =((1492+0.525×8)×1.3)/(0⋅61×5.1)
=4989.5W ≈ 5000W

Selection of a light dependent resistor (LDR)
 >LDR datasheet specifications
 >Power dissipation at 30°C = 250mW
 >Current = 75mA
 >From voltage divider circuit
 >π‘‰π‘œπ‘’π‘‘=(R/(LDR+R))𝑋 𝑉𝑖𝑛
 >Vout = 250mW/75 mA
 3.33𝑉=(10k/(LDR+10k))𝑋 5𝑉
 LDR = 4.99k ≈ 5kΞ©




Post a Comment

1 Comments

  1. Anonymous24.3.23

    So amazing πŸ₯°πŸ₯°πŸ₯°

    ReplyDelete